Përdoruesi:Armend/nënfaqe: Dallime mes rishikimesh
Armend (diskuto | kontribute) |
Armend (diskuto | kontribute) |
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Rreshti 106: | Rreshti 106: | ||
:<math>t(c)=(t_0,t_1,...,t_p)\,</math> |
:<math>t(c)=(t_0,t_1,...,t_p)\,</math> |
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where <math>t_j,j\in I_{p+1}\,</math> denote number of terms of sequence c thats are equal at j, is called trace of c. |
where <math>t_j,j\in I_{p+1}\,</math> denote number of terms of sequence c thats are equal at j, is called trace of c.<br> |
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Is clear that terms of trace fulfills the conditions |
Is clear that terms of trace fulfills the conditions |
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Rreshti 144: | Rreshti 144: | ||
Reasons for that name are because I suppose that: |
Reasons for that name are because I suppose that: |
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Claim:For each finite sequence <math>a\,</math> of natural numbers exists natural number n such that |
Claim:For each finite sequence <math>a\,</math> of natural numbers exists natural number n such that |
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#Sequence <math>a\,</math> is of type <math>B\,</math> if its converge to H from B for example sequence (2,3) is of type B because |
:<math>t^n(a)\in H\,</math> in other words each sequence converges to H. |
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#Sequence <math>a\,</math> is of type <math>B\,</math> if its converge to H from B for example sequence |
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(2,3) is of type B because |
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: <math>t^3((2,3))=(0,0,2)\in B\,</math> |
: <math>t^3((2,3))=(0,0,2)\in B\,</math> |
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Rreshti 154: | Rreshti 157: | ||
:<math>t^6((0))=(1,2)\in R\,</math> |
:<math>t^6((0))=(1,2)\in R\,</math> |
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Is my assumption true and if it is true how to decide of which type is any given finite sequence of natural |
Is my assumption true and if it is true how to decide of which type is any given finite sequence of natural<br> |
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numbers, can be done any programme or algorithm. |
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Firstly we reduce the problem to an analysis of the cases <math>m\le2\,</math>. |
Firstly we reduce the problem to an analysis of the cases <math>m\le2\,</math>. |
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I'll write <math>t^k\,</math> for the <math>k\,</math>-fold composition of <math>t\,</math> with itself, so that <math>t^1=t\,</math>, <math>t^2=t\circ t\,</math>, etc. |
I'll write <math>t^k\,</math> for the <math>k\,</math>-fold composition of <math>t\,</math> <br> |
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with itself, so that <math>t^1=t\,</math>, <math>t^2=t\circ t\,</math>, etc. |
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I'll also write <math>|{c}|\,</math> for the number of distinct elements of the <math>m\,</math>-tuple <math>c=(c_0,c_1,\dots,c_{m-1})\in\mathbb{N}^m\,</math>. |
I'll also write <math>|{c}|\,</math> for the number of distinct elements of the <br> |
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<math>m\,</math>-tuple <math>c=(c_0,c_1,\dots,c_{m-1})\in\mathbb{N}^m\,</math>. |
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And I'll write things like <math>(n,m^k,p)\,</math> as shorthand for <math>(n,m,m,\dots,m,p)\,</math> where <math>m\,</math> is repeated <math>k\,</math> times. |
And I'll write things like <math>(n,m^k,p)\,</math> as shorthand for <math>(n,m,m,\dots,m,p)\,</math><br> |
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where <math>m\,</math> is repeated <math>k\,</math> times. |
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A first observation is that |
A first observation is that |
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Rreshti 165: | Rreshti 172: | ||
:<math>t(c)=t(c')\,</math> for any permutation <math>c'\,</math> of <math>c\,</math>. |
:<math>t(c)=t(c')\,</math> for any permutation <math>c'\,</math> of <math>c\,</math>. |
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Lemma: <math>|t^2(c)|\geq |c|\,</math> if and only if either <math>|{c}|=1\,</math>, or <math>|{c}|=2\,</math> and <math>c=(a,b^{|c|-1})\,</math> (up to permutation) where <math>a\ne b\,</math>. |
Lemma: <math>|t^2(c)|\geq |c|\,</math> if and only if either <math>|{c}|=1\,</math>, or <math>|{c}|=2\,</math> <br> |
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and <math>c=(a,b^{|c|-1})\,</math> (up to permutation) where <math>a\ne b\,</math>. |
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Proof: We have <math>|t^2(c)|=\max\{t_0,\dots,t_{p+1}\}\,</math>, so <math>|t^2(c)|\ge |c|\,</math> if and only if <math>|t^2(c)|\in \{|c|,|c|+1\}\iff \{|c|-1,|c|\}\cap \{t_0,\dots,t_p\}\ne \emptyset\,</math>, which is equivalent to the conditions above. |
Proof: We have <math>|t^2(c)|=\max\{t_0,\dots,t_{p+1}\}\,</math>, so <math>|t^2(c)|\ge |c|\,</math> if and only if <br> |
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<math>|t^2(c)|\in \{|c|,|c|+1\}\iff \{|c|-1,|c|\}\cap \{t_0,\dots,t_p\}\ne \emptyset\,</math>, which is equivalent to the conditions above. |
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Claim: If <math>m=|c|\ge 3\,</math> then <math>|t^n(c)|<|c|\,</math> for some <math>n\ge 1\,</math>. |
Claim: If <math>m=|c|\ge 3\,</math> then <math>|t^n(c)|<|c|\,</math> for some <math>n\ge 1\,</math>. |
Versioni i datës 17 korrik 2011 13:37
Compart
Gjatësia valore e një vale sinusoidale është perioda hapësinore e saj dmth distanca për të cilën forma e valës përsëritet. Zakonisht konsiderohet largësia në mes dy pikave korresponduese të njëpasnjëshme me fazë të njejtë, siç janë majat e valës, pika më e ulët e valës etj. Ajo shënohet me simbolin llambda (λ) i cili përdoret edhe për shënimin e valëve josinusoidale.
Numri i thjeshtë
Ky artikull në encikloopedinë ruse është zgjedhur ndër artikujt më të mirë prandaj unë vendosa që ta përkthej dhe besoj se përkthimi është i kualitetit të lartë ka disa probleme të vogla me referencat. Unë mendoj se edhe në vikipedinë shqipe meriton të citohet si ndër artikujt më të mirë. Do të kisha dashur që këtë artikull d.m.th përkthimin e tij ta vlerësonte një matematikan profesionist por për fat të keq momentalisht nuk i kemi.--Armend 8 Mars 2009 00:57 (CET)
Merre spell-checker, se po më duket ka disa gabime. Une po e fusë por prap se prap ti kontrollo.--Hipi Zhdripi 8 Mars 2009 02:04 (CET)
- polinomiale, pseudorastësishëm - nuk e kap spell çekiqi--Hipi Zhdripi 8 Mars 2009 02:13 (CET)
Ka më se një vit që këtë artikull e kam kandiduar për artikull perfekt por ka kaluar pa u vërejtnga përdoruesit tjerë. Ju lutem votoni dhe komentoni.--Armend 5 Qershor 2010 13:19 (CEST)
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==S==tampa
Ky përdorues është adhurues i Leonhard Eulerit. |
Koordinata polare
Le të jetë dhënë një gjysmëdrejtëzë e orientuar të cilën e quajmë edhe bosht në një rrafsh të caktuar. Origjinën e gjysmëdrejtëzës do ta quajmë pol atëherë pozita e çdo pike të këtij rrafshi mund të përcaktohet me largësinë e saj nga poli dhe me këndin të cilin e formon rrezja e kësaj pike me boshtin polar.
Poli është analog me origjinën e sistemit koordinativ këndrejt, dhe rrezja nga poli me drejtim të fiksuar quhet bosht polar. Largësia r nga poli quhet koordinatë radiale ose rreze, ndërsa këndi që rrezja e pikës e formon me boshtin polar quhet koordinatë këndore
Numrat
Në fillim ishin numrat natyral pastaj lindën numrat tjerë.
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Numrat kompleks | Kuaternionet |
Compositions of natural numbers over arithmetic progressions
Denote by
the set Each m-sequence of natural numbers that fulfill the conditions.
- ,
is called composition of natural number k in m parts over
Denote by the set of compositions of natural number k in m parts over
generating function
now from binomial formula we get
if now substitute thent taking in account that follow
that
trace of sequences
Trace of sequence
Denote by
the set of natural numbers and by
the set of natural numbers lesser than given natural number m. Lets
a m-sequence of natural numbers and
the greatest term of sequence c then the sequence
where denote number of terms of sequence c thats are equal at j, is called trace of c.
Is clear that terms of trace fulfills the conditions
Denote by
1.The set of sequences
that is cycle of length 6 is called bracelet of sequences because for each sequence c from B holds
2.The set of sequences
that is cycle of length 2 is called ring of sequences because for each sequence c from R holds
The set
is called black hole of sequences
Reasons for that name are because I suppose that:
Claim:For each finite sequence of natural numbers exists natural number n such that
- in other words each sequence converges to H.
- Sequence is of type if its converge to H from B for example sequence
(2,3) is of type B because
- And sequences that converges to H from R are of type R for example the sequence (0) is of type R because
Is my assumption true and if it is true how to decide of which type is any given finite sequence of natural
numbers, can be done any programme or algorithm.
0
Firstly we reduce the problem to an analysis of the cases .
I'll write for the -fold composition of
with itself, so that , , etc.
I'll also write for the number of distinct elements of the
-tuple .
And I'll write things like as shorthand for
where is repeated times.
A first observation is that
- for any permutation of .
Lemma: if and only if either , or
and (up to permutation) where .
Proof: We have , so if and only if
, which is equivalent to the conditions above.
Claim: If then for some .
Remark: This allows us to reduce to the case to establish the claim in the question, if it's true. Proof of the claim: this is a case-by-case analysis.
- If then will do by the lemma.
- If , either , or , or , or where , so that , or where . In this case, , , .
- If or then , so and $|t^6(c)|
- If and is not of the form (up to permutation) then by the lemma.
- If and , suppose first that then then is a permutation of , so the previous argument applies.
So we prove that, the assumption is true for , so it appears to be true in general.
1
If , for some . If , , and either , in which case , and . If , , and we’re in the first case.
2
Now let and . Observation: If , , while , so whenever .
- If , , and .
- If , , and .
- If , ; if , ; and if , .
- If , , and , where , whence
- by the Observation.
Now assume without loss of generality that $x Observation ensures that
- .
-- Brian M. Scott 8 hours ago