Rezultatet e kërkimit

n − k ) ! = n ( n − 1 ) ( n − 2 ) ⋯ ( n − k + 1 ) k ( k − 1 ) ( k − 2 ) ⋯ 1 {\displaystyle {n \choose k}={\frac {n!}{k!(n-k)!}}={\frac {n(n-1)(n-2)\cdots...

etj. n ( n − 1 ) ( n − 2 ) ⋯ ( n − k + 1 ) k ! = { n ! k ! ( n − k ) ! nëse  k ∈ [ [ 0 ; n ] ] (1) 0 përndryshe {\displaystyle {\frac {n(n-1)(n-2)\cdots...

( k ) = Pr ( X = k ) = ( K k ) ( N − K n − k ) ( N n ) , {\displaystyle p_{X}(k)=\Pr(X=k)={\frac {{\binom {K}{k}}{\binom {N-K}{n-k}}}{\binom {N}{n}}}...

F n ( f ) ] ( x ) = 1 n π ∑ k = − ∞ ∞ e ( − n ( k n − x ) 2 ) f ( k n ) {\displaystyle [{\mathcal {F}}_{n}(f)](x)={\frac {1}{\sqrt {n\pi }}}\sum _{k=-\infty...

∑ k = 0 K Pr ( X = k ) = ∑ k = 0 K ( k + r − 1 k ) ( N − r − k K − k ) ( N K ) = 1 ( N K ) ∑ k = 0 K ( k + r − 1 k ) ( N − r − k K − k ) = 1 ( N K ) (...

n , k ) = [ n k ] = | s ( n , k ) | = ( − 1 ) n − k s ( n , k ) {\displaystyle c(n,k)=\left[{n \atop k}\right]=|s(n,k)|=(-1)^{n-k}s(n,k)} (me "s" të...

Faktorieli përkufizohet me formulën n ! = ∏ k = 1 n k ∀ n ∈ N . {\displaystyle n!=\prod _{k=1}^{n}k\qquad \forall n\in \mathbb {N} .\!} si rrjedhim kemi se 0...

bashkëtingëllore. Bashkëtingëllorja k. Shkronja k. Tingulli k. Si emër femrorë Bashkëtingëllorja dhe shkronja k. K-ja e madhe (e vogel). K-ja e dorës (e shtypit)....

= d e f   ∑ k = 1 N m k ( r k 2 δ i j − r k i r k j ) {\displaystyle I_{ij}\ {\stackrel {\mathrm {def} }{=}}\ \sum _{k=1}^{N}m_{k}(r_{k}^{2}\delta _{ij}-r_{ki}r_{kj})\...

∼ lim n → ∞ ∑ k = 0 n f ( k ) ( x 0 ) k ! ( x − x 0 ) k . {\displaystyle f(x)\sim \lim _{n\to \infty }\sum _{k=0}^{n}{\frac {f^{(k)}(x_{0})}{k!}}(x-x_{0})^{k}...

; n ) = 1 ( n − 1 ) ! ∑ k = 0 n ( − 1 ) k ( n k ) ( x − k ) + n − 1 {\displaystyle f_{X}(x;n)={\frac {1}{(n-1)!}}\sum _{k=0}^{n}(-1)^{k}{n \choose k}(x-k)_{+}^{n-1}}...

n=1. -Hapi 2 :Supozojmë se është e vërtetë për n=k , 1 2 + 2 2 + 3 2 + . . . + k 2 = k ( k + 1 ) ( 2 k + 1 ) 6 {\displaystyle 1^{2}+2^{2}+3^{2}+...+k^{2}={\frac...

n − k e − k ( n − k ) n − k k ! = n n ( λ n ) k ( 1 − λ n ) n − k e − k n n − k ( 1 − k n ) n − k k ! = λ k ( 1 − λ n ) n − k e − k ( 1 − k n ) n − k...

jepet nga: x n = 1 N ∑ k = 0 N − 1 X k ⋅ e i 2 π k N n {\displaystyle x_{n}={\frac {1}{N}}\sum _{k=0}^{N-1}X_{k}\cdot e^{i2\pi {\tfrac {k}{N}}n}} Ky shembull...

Pr ( k ; n , p ) = Pr ( X = k ) = ( n k ) p k ( 1 − p ) n − k {\displaystyle f(k,n,p)=\Pr(k;n,p)=\Pr(X=k)={\binom {n}{k}}p^{k}(1-p)^{n-k}} për k = 0, 1...

) n d x = x ∑ k = 0 n ( − 1 ) n − k n ! k ! ( ln ⁡ x ) k {\displaystyle \int (\ln x)^{n}\;dx=x\sum _{k=0}^{n}(-1)^{n-k}{\frac {n!}{k!}}(\ln x)^{k}} ∫...

lim n → ∞ ( − log ⁡ n + ∑ k = 1 n 1 k ) = ∫ 1 ∞ ( − 1 x + 1 ⌊ x ⌋ ) d x . {\displaystyle {\begin{aligned}\gamma &=\lim _{n\to \infty }\left(-\log n+\sum...

shkallës k ka formën: a n = c 1 a n − 1 + c 2 a n − 2 + . . . + c k a n − k {\displaystyle {\displaystyle a_{n}=c_{1}a_{n-1}+c_{2}a_{n-2}+...+c_{k}a_{n-k}}}...

; n ) = n 2 ( n − 1 ) ! ∑ k = 0 n ( − 1 ) k ( n k ) ( n x − k ) n − 1 sgn ⁡ ( n x − k ) {\displaystyle f_{X}(x;n)={\frac {n}{2(n-1)!}}\sum _{k=0}^{n}(-1)^{k}{n...

lim n → ∞ 1 n ∑ k = 1 n ( ⌈ n k ⌉ − n k ) , {\displaystyle \gamma =\lim _{n\to \infty }{\frac {1}{n}}\sum _{k=1}^{n}\left(\left\lceil {\frac {n}{k}}\right\rceil...